12b^2-36b+30=3

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Solution for 12b^2-36b+30=3 equation: 



12b^2-36b+30=3

We move all terms to the left:

12b^2-36b+30-(3)=0

We add all the numbers together, and all the variables

12b^2-36b+27=0

a = 12; b = -36; c = +27;
Δ = b2-4ac
Δ = -362-4·12·27
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$b=\frac{-b}{2a}=\frac{36}{24}=1+1/2$

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